Caesar cipher and ROT13 API: shift letters by any amount

$0.01 per call · failed calls are never charged · no account or API key needed

Encode or decode text with a Caesar cipher: every letter A-Z shifted by 1-25 places (13, the default, is ROT13), case kept, digits and punctuation untouched. decode=true shifts back. Use for puzzles, spoiler hiding and teaching; it is not encryption.

When to use it

Run it free (25 free calls) Buy credits by card (from $5) Example result (JSON)

Try it with your own inputs

The text

Uses one of your 25 free calls. Nothing is charged, and a call that fails is not counted.

Inputs

NameTypeDescription
text (required)stringThe text
shiftintegerPlaces to shift, -25 to 25 (default 13 = ROT13)
decodestringtrue to shift back

Request

Over HTTP, with a card key from /credits:

curl -H "Authorization: Bearer adt_…" "https://agent-data-tools.revmesh2074.workers.dev/text/caesar?text=Hello%2C%20World!"

Or one of your 25 free calls, no key:

curl "https://agent-data-tools.revmesh2074.workers.dev/text/caesar?text=Hello%2C%20World!&trial=1"

Without a key, the same URL answers 402 Payment Required with x402 and MPP terms, so an agent with a wallet pays per call in USDC (Base, Polygon, Arbitrum or Solana over x402; Base or Tempo over MPP) and retries.

Example result

{
  "result": "Uryyb, Jbeyq!",
  "shift": 13
}

From an AI agent (MCP)

Add the MCP server to Claude, Cursor or any MCP client. This tool is text_caesar, and the first 25 successful calls are free:

https://agent-data-tools.revmesh2074.workers.dev/mcp

Questions

Is this encryption?

No, it is a simple letter shift and offers no security.

What happens to digits and punctuation?

They are left unchanged; letters keep their case.

How do I pay?

Each successful call costs $0.01; failed calls are not charged. The first 25 calls are free. Then pay with card credits (from $5) or per call in USDC over x402 or MPP. No account or API key is needed.

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